00:01
Hello, so here we have the g of x is equal to e to the x.
00:04
So for part a here, taking the derivative, well, the derivative of e to the x is e to the x.
00:09
And the derivative of, again, is e to the x and then e to the x and then e to the x.
00:13
So the nth derivative of x here, well, the derivative is always going to be e to the x.
00:20
So pointing x minus a equals zero, we have x equals a.
00:24
And that's going to imply then that the nth derivative is going to, the nth derivative evaluated at a is going to be equal to just e to the a.
00:37
So then our tailor polynomial becomes g of x is going to be equal to e to the a and then times the sum where we have k going from zero to infinity of x minus a to the k divided by k factorial.
01:01
All right.
01:01
And then from part b, we have that, well, again, g of x is equal to e to the a times the sum of x minus a to the k over k factorial...