00:01
Now, on this problem, we've been in the following joint distribution, and we like to find the marginals.
00:05
Now, in order to find the marginal distribution of x, we integrate out the y.
00:12
And so y can go from zero to once.
00:14
We integrate two -thirds times x plus 2y, d -y.
00:23
And so this becomes two -thirds x, y, plus two -thirds, y squared, evaluated from y is zero to one.
00:42
Putting in 1 for y, putting in 0 for y, and then subtracting gives us 2 thirds x plus 2 thirds and so this is our marginal distribution of x.
01:00
Now for our marginal distribution for y, we do the same thing, we just integrate out the y.
01:06
And so f y of y is the integral from 0 to 1 of 2 thirds times x plus 2 y d x, integrating out the x.
01:22
And so this becomes one -third x squared plus four -thirds xy, evaluated from x's zero to one...