Question
A fifteen-watt heater is used to heat a monatomic ideal gas at a constant pressure of$7.60 \times 10^{5}$ Pa. During the process, the $1.40 \times 10^{-3} \mathrm{m}^{3}$ volume of thegas increases by 25.0$\% .$ How long was the heater on?
Step 1
0$\%$. We can calculate the change in volume ($\Delta V$) by multiplying the initial volume by 0.25. \[ \Delta V = 0.25 \times 1.40 \times 10^{-3} \mathrm{m}^{3} = 0.00035 \mathrm{m}^{3} \] Show more…
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A fifteen-watt heater is used to heat a monatomic ideal gas at a constant pressure of $7.60 \times 10^{5} \mathrm{~Pa}$. During the process, the $1.40 \times 10^{-3} \mathrm{~m}^{3}$ volume of the gas increases by $25.0 \%$. How long was the heater on?
A monatomic ideal gas is heated while at a constant volume of $1.00 \times 10^{-3} \mathrm{m}^{3},$ using a ten-watt heater. The pressure of the gas increases by $5.0 \times 10^{4}$ Pa. How long was the heater on?
Interactive Solution 15.37 at offers one approach to this problem. A fifteen-watt heater is used to heat a monatomic ideal gas at a constant pressure of $7.60 \times 10^{5} \mathrm{~Pa}$. During the process, the $1.40 \times 10^{-3} \mathrm{~m}^{3}$ volume of the gas increases by $25.0 \% .$ How long was the heater on?
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