00:01
So we'd like to find first a vector parallel to the line of intersection between two planes.
00:05
We've seen earlier that we can find that by cross -producting their normal vectors.
00:11
So normal vector of this first guy is going to be 2, negative 1, negative 3, just pulling up the coefficients.
00:19
Normal vector of the second guy is 1, 1, 1.
00:22
We plug in our i, j, k to find the cross product.
00:27
The i times negative 1 plus 4 is 3, or negative 1 plus 3, i'm sorry, is 2 times i hat, plus, let's see, that will be negative 3 minus 2 is negative 5.
00:46
And then, excuse me, here we get 2 plus 1 is 3.
00:50
That's 3k.
00:51
So our normal vector, or excuse me, our vector that is parallel to the line of intersection will 2 minus 5, 3.
01:01
Or 2 times i minus 5 times j.
01:04
J, not i.
01:07
Let's make that clearer...