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Problem

Suppose hydrogen and oxygen are diffusing through…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66

Problem 65 Hard Difficulty

(a) Find the average time required for an oxygen molecule to diffuse through a 0.200-mm-thick tear layer on the cornea.
(b) How much time is required to diffuse 0.500 $\mathrm{cm}^{3}$ of oxygen to the cornea if its surface area is 1.00 $\mathrm{cm}^{2} ?$

Answer

(a) $t=20 \mathrm{s}$
(b) $t=1.25 \times 10^{4} \mathrm{s}=3.47 \mathrm{h}$

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Physics 101 Mechanics

College Physics for AP® Courses

Chapter 12

Fluid Dynamics and Its Biological and Medical Applications

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Video Transcript

So we want to find out how long it will take for here to defuse or in a molecule to diffuse their wantto. Mm. So you simply is the formula equal, Toto to lady, which means times equal to the square by two d. So that's zero point to entertain. Part minus 23 all squared, divided by two in tow. The division constant. It is 1.0 doing to £10 my smile. We're considering the diffusion constant in water because cornea is mainly water. So on This turns out to be 20 seconds. Now for the second case going to find out this volume. How long it'll take for this volume off oxygen? Sure. Gettinto Cardia, off area. One point wants it to be the square for that. Think of it like this. Let's say this is our car near with our area on our oxygen is in a cubicle farm in front of it. Now, as time goes on, this whole cube moves into the cornea. It is a sequel. Do root too needy. So the volume is simply area times this distance. So that's area in total Todt. So the time is simply volume developed area All is fair. In one bite would be simple as that. So that is 0.5 into 10 5 minus Who was like you? I'm sorry. 0.5 centimeter cube on one centimeter cube. A stamp on my six meter cube, divided by our idea, is one centimeter square. So that's one minus four meter squared I was to be so that's two in tow. Our refuge in Constant is and they want on Skeletal into 10th on minus nine. Have you known about it constantly? Cool party. Three seconds. This is how long it would take for little quantify centimeter cube off gas too seeping. Do one centimeter square corny.

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