00:01
Okay, so we know that when the density of a solid is constant, then the center of mass becomes decentroid.
00:07
So in this case, we get that row of x, y, z is going to be equal to some constant k.
00:16
And the solid given by h is the set of, so row and then theta fee, where we have row between zero and a, and then theta between zero and two pi, and fee between zero and pi over two.
00:31
We get that the moment m here is the triple integral over row of xyz dv so we get k and then times the integral from zero to two pi and then we have times the integral from zero to pi over two and then the integral from zero to a of row squared and then sign of fee and then we have um, d row, theta.
01:07
Okay, so we um, integrate from the inside out here, and then we're going to end up with, k times, row cubed, uh, row cubed over three, uh, where we are evaluating from zero to a, and then we have times theta, evaluating from zero to two pi, and then negative cosine, of fee evaluating from zero to pi over two.
01:40
Okay, so that's going to give us two -thirds a cubed pi times k.
01:51
So we get the moment, the first moment along the y is going to be zero, and then likewise along the y and the x, but then along x, y, we then get x, we then get k times row to the fourth over four, evaluating from 0 to a times theta from 0 to 2 pi, and then times negative 1 fourth, cosine of 2 feet, evaluating from 0 to pi over 2, and that's going to give us a to the 4th over 4 times pi k...