00:01
In this problem, we will be looking at the phenomenon of pair production when a proton antiproton pair spontaneously appears when there is enough energy.
00:14
To find the energy required to produce an electron positon pair, first we need to consider how much rest mass energy does an electron positron pair have.
00:23
So both the electron, sorry, both the proton and the antiproton have the same mass.
00:34
Which is equal to one atomic mass unit that is 1 .66 into 10 to the negative 27 kilograms.
00:46
So two of these will have the total mass m has two times 1 .66 into 10 to the negative 27.
01:00
That is just 3 .33 into 10 to the negative 27.
01:18
To produce this much mass, we'll simply use the mass energy equivalents to find out how much energy it's required to produce this much mass.
01:33
And we'll substitute our mass is 3 .32 into 10 to the negative 27 kilograms and the speed of light as 3 into 10 to the 8 meters per second and we're going to squared.
01:49
And then we will evaluate this expression using a calculator.
01:55
This gives 2 .99 into 10 to the negative 10 joules as are required energy...