00:01
So for this problem, we're going to need to find the first 490 terms, the chlorine series followed by power series representation, and its interval of convergence.
00:11
So the first thing we have is that this is going to be very similar to natural log of x plus 1, since that's equal to x, minus x squared over 2, plus x to the third over 3, and x to the fourth over 4.
00:30
The main difference is that when we take the derivative of this here, we get 1 over lln of 3 times everything else that we'll have afterwards.
00:43
So the main difference is that we're multiplying all of this by 1 over ln3.
00:49
So we have as the first term, it's x over ln3 minus x squared over 2, ln of 3 plus x to the 3 over 3, plus x to the 3rd over 3, 1⁄2 ,000 3, plus x to the 3th of 4th of 2.
01:02
Over 4, l of 3.
01:07
So that gives us the summation of, so x to the k over ln of 3 times k down here.
01:23
And we're just missing this from k equals 1 to infinity.
01:34
We have negative 1 to the k plus 1 here.
01:38
So that's the full summation there...