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Problem

(a) Find the intervals on which $f$ is increasing…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66

Problem 2 Medium Difficulty

(a) Find the intervals on which $f$ is increasing or decreasing.
(b) Find the local maximum and minimum values of $f .$
(c) Find the intervals of concavity and the inflection points.
$f(x)=4 x^{3}+3 x^{2}-6 x+1$

Answer

A. Increasing in $(-\infty,-1) \cup\left(\frac{1}{2}, \infty\right)$
Decreasing in $\left(-1, \frac{1}{2}\right)$
B. The local maximum is $f(-1)=6,$ so $(-1,6)$
The local minimum is $f\left(\frac{1}{2}\right)=-\frac{3}{4},$ so $\left(\frac{1}{2},-\frac{3}{4}\right)$
C. Inflection point at $x=-\frac{1}{4}$
Concave downward $\left(-\infty,-\frac{1}{4}\right)$
Concave upward in $\left(-\frac{1}{4}, \infty\right)$

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Problem 1
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Problem 6
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Problem 9
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Problem 11
Problem 12
Problem 13
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Problem 15
Problem 16
Problem 17
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Problem 19
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Problem 26
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Problem 55
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Video Transcript

for this question. We have three different parts. So let's first right out of the first of the narrative and the second that curative. So we were right out the front of the irritate. We can just do the baby affect her, factoring into something like this which directly gives us the roots off this first of the theater. And for the second of their two, we have did you for explosives. So probably we want to find the increasing decrease interval. So we just let if prime off X equals zero. So we have exit post minus one. The exit cross will have, which means we have three step intervals from negative infinity to negative one thrown negative 1 to 1/2 for on one have to pause appear taking unity. So for the first interval, if prime of X is positive, the muse f is increasing on the second terrible If prime affects this connective so every is decreasing. On the last interval the first of the narrative eight supportive. So it's increasing. I face increasing again and the footprint leave property is directly related to party. We have a local necks. We have a local maximum at X equals two minus one because, um, when X equals two minus one the function on the left the function is increasing and the on the right the function istea crazy. So it's ah, peak. Honestly, value will be a minus one. There's six and for the same reason we have a local Minuteman that X equals to one has so a 4 4.5 equals two minus three or four. And for the concave, it ease way we look at the second the narrative and it just let the second narrative because it's euro the solution will g minus 1/4. Uh, since we only have one solution, we have to stop being talk of us from next If he obviously tonight give wonderful on the phone connective 1/4 to positive unity. So over the first interval, the second of narrative, it's negative. The music conclave hung worked and the over the second terrible on the second of curative is positive. That means it's the collectivity is upward and this is the conservatives are different around X equals to one or four. So we have a reflection point. But but which? Um yes at X equals two minus wonderful

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