00:01
For part a of this problem, we are asked to find the mclaurin series for the polynomial f of x equals 1 plus 2x minus x squared plus x cubed.
00:09
The first thing that we'll note is that f prime of x is going to equal.
00:13
So we lose that 1 and we have 2 and then minus 2x plus 3x squared.
00:20
So evaluating that at 0, so we have f prime of 0, that's just going to be 2.
00:26
Then the second derivative, evaluated that x, is going to knock off that two, and we're left with negative two, then plus 6x, and f double prime of 0 is going to equal negative 2, then f triple prime of x is going to, well, we'll knock off that negative 2, and we'll just be left with a 6, so we'll have that f triple prime of 0 is equal to 6, and then the 3.
00:59
Fourth or we can note that once we get to the fourth derivative, we just get zero.
01:06
So everything subsequent would be zero as well.
01:09
Substituting that into our mclaurin series expression, we would see that, well, we'd have the first term would be from evaluating our function at zero, which would be one.
01:20
So i'll write half of x is approximately.
01:24
One.
01:25
And then we add on 2 times x divided by 1 factorial, so divided by 1...