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(a) Find the maximum number of lines per centimeter a diffraction grating can have and produce a maximum for the smallest wavelength of visible light. (b) Would such a grating be useful for ultraviolet spectra? (c) For infrared spectra?

A. $N=26,300$ lines/cmB. Therefore, this result is feasible. Hence, the given grating will be useful for ultra violetspectra.C. It is well known that value of sine function can never be greater than $1 .$ Hence, the givengrating is not useful for infrared spectra.

Physics 103

Chapter 27

Wave Optics

University of Michigan - Ann Arbor

University of Washington

McMaster University

Lectures

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what? Hey, Number off lines and is equal to a number of lines. Person per meter is equal to one or d the DEA's the slip separation. So, Deke and rude and is, um, one time repellent. Um so prevalent we have here. He's 490 meters. Been working in two meters. We have well, but multiply contemptible on minus night. Excuse us a distance. So then the number off lines we can find it by dividing this distance which is 400 400 centimeters. So the writing, 490 meters we get here. Um, two. 25,000 25,000 lines. 25,000 lines per centimeter In part B. The slit suppression should be equal or greater than so. Um do you should be equal or greater them incident prevalent. So let's say incident revel And we have I, uh, for the defection to Walker since the since it is greater than ultra wallet. So the infection is a capable for producing ultraviolet well draw, while so you'II in C, the given by violent is smaller than infrared. Then this try affection is not capable of producing a friction order for the inn for a rid spectrum

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