00:01
We are asked to use equation 3 .5 from the textbook shown here to solve for the mean and variance of the gamma distribution shown here.
00:15
Now if we're finding the mean, obviously we want to find the expectation on x.
00:21
And if we're finding the variance, in order to use the variance shortcut formula, we want to find the expectation on x squared as well.
00:31
With that in mind, the expected value of x to the exponent k, by definition is given as follows.
00:43
It's the integration over the entire domain of the distribution of x to the exponent k times the following.
01:25
Now as we can see this component is of a similar form to this component here.
01:33
And we can also note that this part is not a function of x so it can be moved out of the integral.
01:44
And so we have, and now combining these two factors.
02:00
Now, to make use of this formula, we note that instead of alpha minus 1, we have alpha minus 1 plus k, so we can evaluate this integral as follows.
02:47
It's going to be beta to the exponent alpha plus k, plus gamma of alpha plus k.
03:02
Now this combination results in beta to the exponent k, and then we have gamma of alpha plus k over gamma of alpha.
03:23
And now we can solve for the expected value, so that's x to the exponent 1.
03:31
So that gives beta to the exponent alpha, or rather that's beta to the exponent 1 times the following...