Question
(a) find the standard form of the equation of the ellipse, (b) find the center, vertices, foci, and eccentricity of the ellipse, and (c) sketch the ellipse. Use a graphing utility to verify your graph.$$x^{2}+9 y^{2}=36$$
Step 1
The standard form of an ellipse is $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$. So, we divide the given equation by 36 to get it in the standard form. $$\frac{x^2}{36} + \frac{9y^2}{36} = 1$$ This simplifies to: $$\frac{x^2}{6^2} + \frac{y^2}{2^2} = 1$$ Show more…
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(a) find the standard form of the equation of the ellipse, (b) find the center, vertices, foci, and eccentricity of the ellipse, and (c) sketch the ellipse. Use a graphing utility to verify your graph. $$9 x^{2}+4 y^{2}+36 x-24 y+36=0$$
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(a) find the standard form of the equation of the ellipse, (b) find the center, vertices, foci, and eccentricity of the ellipse, and (c) sketch the ellipse. Use a graphing utility to verify your graph. $$36 x^{2}+9 y^{2}+48 x-36 y+43=0$$
(a) find the standard form of the equation of the ellipse, (b) find the center, vertices, foci, and eccentricity of the ellipse, and (c) sketch the ellipse. Use a graphing utility to verify your graph. $$9 x^{2}+4 y^{2}-54 x+40 y+37=0$$
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