Here, $a=\frac{1}{2}$ and $b=-3$. So, the x-coordinate of the vertex is $-\frac{-3}{2*\frac{1}{2}}=3$. Substituting $x=3$ in the equation, we get $f(3)=\frac{1}{2}*3^{2}-3*3+\frac{5}{2}=\frac{9}{2}-9+\frac{5}{2}=-2$. So, the vertex of the parabola is $(3,-2)$.
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