To find the vertex of this function, we need to convert it into the standard vertex form which is $g(x)=a(x-h)^{2}+k$. Here, $g(x)=x^{2}-6$ can be written as $g(x)=(x-0)^{2}-6$. Comparing this equation with the standard vertex form, we get $h=0$ and $k=-6$.
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