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# (a) Find $y'$ by implicit differentiation.(b) Solve the equation explicitly for y and differentiate to get $y'$ in terms of $x.$(c) Check that your solutions to part (a) and (b) are consistent by substituting the expression for $y$ into your solution for part (a). $9 x^2 - y^2 = 1$

## a. $\frac{9 x}{y}$b. $\pm \frac{9 x}{\sqrt{9 x^{2}-1}}$c. From part $(a), y^{\prime}=\frac{9 x}{y}=\frac{9 x}{\pm \sqrt{9 x^{2}-1}},$ which agrees with part

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