We can use the equation $v=\sqrt{2gh}$, where $g$ is the acceleration due to gravity and $h$ is the height. Substituting $g=32.174 \, \text{ft/s}^2$ and $h=275 \, \text{ft}$, we get $v=\sqrt{2 \times 32.174 \times 275} = 133.3 \, \text{ft/s}$.
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