Question
A first-order reaction $\mathrm{A} \longrightarrow \mathrm{B}$ has the rate constant $k=3.2 \times 10^{-3} \mathrm{s}^{-1} .$ If the initial concentration of $\mathrm{A}$ is $2.5 \times 10^{-2} \mathrm{M},$ what is the rate of the reaction at $t=660 \mathrm{s} ?$
Step 1
The first-order integrated rate law is given by: \[ \ln \left( \frac{[A]_t}{[A]_0} \right) = -kt \] where $[A]_t$ is the concentration of A at time t, $[A]_0$ is the initial concentration of A, k is the rate constant, and t is the time. Show more…
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A first-order reaction A ¡ B has the rate constant k = 3.2 * 10-3 s-1. If the initial concentration of A is 2.5 * 10-2 M, what is the rate of the reaction at t = 660 s?
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