00:01
Let us solve the first part of this problem.
00:07
Work done in isobaric process.
00:12
Isobaric means constant pressure process is e multiplied by v2 minus e1.
00:19
Now work done in isometric process is equal to isometric means there won't be any change in volume.
00:32
So it will be p del v.
00:35
So it will be equals to 0 since del v will be 0.
00:41
Hence the work done of the gases in this process is 0.
00:48
Now let us calculate work done in each process in the given question.
00:56
So we will write w12, work done in process from 1 to 2.
01:02
This work done is 0.
01:04
It is because it is an is an isometric process since delta v is equal to 0.
01:12
Now, let us solve the work done in process 2 to 3.
01:18
So, since process 2 to 3 is isobaric, so work done will be t multiplied by v2 minus v1...