00:01
Hi, here in this given problem suppose this is the surface of water in the swimming pool, flashlight at the bottom of the swimming pool represented as f.
00:17
This is at a depth 4 .00 meter below the water surface.
00:27
Its light, light of the ray coming out of the flashlight is striking the water surface.
00:44
If we consider this point to be a, this point to be b, then this ab that is given as 2 .00 meter.
00:59
So, taking this as a right angle triangle we can find this angle theta.
01:06
So, using alternate interior angle, this angle of incidence here that will also be equal to angle theta.
01:17
So, this tan theta or tan i angle of incidence that will be given by perpendicular ab divided by base af means this is 2 .00 meter divided by 4 .00 meter means this is 0 .5.
01:42
So, this angle i angle of incidence will be given by tan inverse 0 .5.
01:50
It is calculated to be equal to 26 .6 degree...