Question
A flat loop of wire consisting of a single turn of crosssectional area $8.00 \mathrm{cm}^{2}$ is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to $2.50 \mathrm{T}$ in 1.00 s. What is the resulting induced current if the loop has a resistance of $2.00 \Omega ?$
Step 1
This is given by the formula: \[ \text{emf} = \frac{d(\Phi)}{dt} \] where \(\Phi = B \cdot A\) is the magnetic flux, \(B\) is the magnetic field, and \(A\) is the area of the coil. Show more…
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A flat loop of wire consisting of a single turn of cross-sectional area 8.00 $\mathrm{cm}^{2}$ is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 $\mathrm{T}$ to 2.50 $\mathrm{T}$ in 1.00 $\mathrm{s}$ . What is the resulting induced current if the loop has a resistance of 2.00$\Omega$ ?
A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 2.50 T in 1.00 s. What is the resulting induced current if the loop has a resistance of 2.00 Ω?
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