Question
A flow of 1 kg/s argon at 300 K and another flow of $1 \mathrm{kg} / \mathrm{s} \mathrm{CO}_{2}$ at $1600 \mathrm{K}$ both at $150 \mathrm{kPa}$ are mixed without any heat transfer. What is the exit $T, P ?$
Step 1
In this case, we have two incoming flows (argon and CO2) and one outgoing flow (the mixture). The equation can be written as: \[m_{Ar}h_{1,Ar} + m_{CO2}h_{1,CO2} = m_{Ar}h_{2,Ar} + m_{CO2}h_{2,CO2}\] Show more…
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A flow of $1 \mathrm{~kg} / \mathrm{s}$ argon at $300 \mathrm{~K}$ and another flow of $1 \mathrm{~kg} / \mathrm{s}$ carbon dioxide at $1600 \mathrm{~K}$, both at $150 \mathrm{kPa}$ are mixed without any heat transfer. What is the exit $T, P ?$
A flow of $1 \mathrm{~kg} / \mathrm{s}$ argon at $300 \mathrm{~K}$ and another flow of $1 \mathrm{~kg} / \mathrm{s}$ carbon dioxide at $1600 \mathrm{~K},$ both at $150 \mathrm{kPa}$ are mixed without any heat transfer. Find the exit T, $P$ using variable specific heats.
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