0:00
Hi, everybody.
00:01
So what are the mass volume flow rates at each line? so we're going to assume air mixture of 7 % for 2 and 21 % of oxygen.
00:10
So the mixture of molecular weight is going to be 0 .21 for the 21 % times 3199 of oxygen plus 0 .79, this is 79 % times 28 .013 of the nitrogen, which is going to be 28 .013 of the nitrogen, which is going to be 28.
00:30
0 .85.
00:32
And a mass concentration of oxygen will go o2.
00:37
Let me 0 .21 times 3 .1 .9 divided by 28 .85.
00:49
And we get 0 .2328.
00:53
And now for the nitrogen 2 ,000, we have 0 .79 times.
01:01
28 .013 divided by 28 .85 equals 0 .76765.
01:14
And now we find the airflow rate of ibmms.
01:23
So the volume flow rate of oxygen air is the outson air is the o2.
01:33
Equals co2 times mv which equals 0 .2328 times 1 and times rottp.
01:48
Okay.
01:50
So now we can finish writing out...