Question
A flywheel of mass $50 \mathrm{~kg}$ and radius of gyration about its axis of rotation of $0.5 \mathrm{~m}$ is acted upon by a constant torque of $12.5 \mathrm{~N}-\mathrm{m}$. Its angular velocity at $t=5$ seconds is(a) $2.5 \mathrm{rad} / \mathrm{s}$(b) $5 \mathrm{rad} / \mathrm{s}$(c) $7.5 \mathrm{rad} / \mathrm{s}$(d) $10 \mathrm{rad} / \mathrm{s}$
Step 1
The moment of inertia is given by the formula $I = m \cdot k^2$, where m is the mass of the flywheel and k is the radius of gyration. Substituting the given values, we get $I = 50 \cdot (0.5)^2 = 12.5 \, \mathrm{kg} \cdot \mathrm{m}^2$. Show more…
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