00:01
We kick a ball with initial velocity 22 .4 meters per second at an angle theta knot equals 49 .0 degrees above the horizontal when we are 39 .0 meters from the goalpost.
00:13
We want to answer the question based on this information alone.
00:16
Does the ball clear the goal post, which is at 3 .05 meters height? and what is the speed, or rather the vertical component of speed, at the post? so to answer this question, we have to use the equations of projectile motion.
00:31
First and foremost, we are given x0.
00:34
X0 equals 0, x -final equal 39 meters, vx0 equals v -0 -cose -theta equals 14 .7 meters per second, and vy equals v0 -syndt, and b -y0 -y -y -y -yer equals v -y -yt equals 16 .9 meters per second.
00:44
Next, we can find the time to reach the goalpost.
00:48
We know that the horizontal component of velocity is constant for project -dial motion, and x -x -0 plus vx -t...