Question
A force acts on a 3 gram particle such that its position $x=3 t-4 t^{2}+t^{3}$, where $x$ is in metre and $t$ is in second. The work done during first $4 \mathrm{~s}$ is(A) $825 \mathrm{~mJ}$(B) $285 \mathrm{~mJ}$(C) $528 \mathrm{~mJ}$(D) Zero
Step 1
The mass of the particle is given as $3g = 3 \times 10^{-3} kg$. Show more…
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A force acts on a $30 \mathrm{~g}$ particle in such a way that the position of the particle as function of time is given by $x=3 t-4 t^{2}+t^{3}$, where $x$ is in metre and $t$ is in second. The work done during the first 4 seconds is (a) 5.28 J (b) $450 \mathrm{~mJ}$ (c) $490 \mathrm{~m} \mathrm{~J}$ (d) $530 \mathrm{~mJ}$
Work, Energy and Power
Round 1
A force acts on a 3 gram particle such that its position x t = 3t - 4t^2 + t^3, where x is in metre and t is in second. The work done during first 4s is
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