A force of 100 N acts on a mass of 5 kg for 10 s. If the mass starts from rest, its velocity

Name: Problem 34, Chapter 4: IIT JEE Super Course in Physics: Mechanics I
Uploaded: 2021-06-11T14:36:22-08:00
Duration: 1 min 21 s
Channel: Ajay Singhal
Description: A force of 100 N acts on a mass of 5 kg for 10 s. If the mass starts from rest, its velocity at the end of 10 s is (a) 2 m s^-1 (b) 20 m s^-1 (c) 200 m s^-1 (d) 50 m s^-1

step 1 So in this question we have a force F equals to 100 Newton which is acting on mass M equals to 5

Question

A force of $100 \mathrm{~N}$ acts on a mass of $5 \mathrm{~kg}$ for $10 \mathrm{~s}$. If the mass starts from rest, its velocity at the end of $10 \mathrm{~s}$ is (a) $2 \mathrm{~m} \mathrm{~s}^{-1}$ (b) $20 \mathrm{~m} \mathrm{~s}^{-1}$ (c) $200 \mathrm{~m} \mathrm{~s}^{-1}$ (d) $50 \mathrm{~m} \mathrm{~s}^{-1}$

   A force of $100 \mathrm{~N}$ acts on a mass of $5 \mathrm{~kg}$ for $10 \mathrm{~s}$. If the mass starts from rest, its velocity at the end of $10 \mathrm{~s}$ is
(a) $2 \mathrm{~m} \mathrm{~s}^{-1}$
(b) $20 \mathrm{~m} \mathrm{~s}^{-1}$
(c) $200 \mathrm{~m} \mathrm{~s}^{-1}$
(d) $50 \mathrm{~m} \mathrm{~s}^{-1}$

IIT JEE Super Course in Physics: Mechanics I

Trishna Knowledge… 1st Edition

Chapter 4, Problem 34

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Solved by Expert Ajay Singhal

06/11/2021

Step 1

The mass starts from rest, so its initial velocity $u = 0$. We need to find the final velocity $v$ at the end of $10 \mathrm{~s}$. Show more…

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A force of $100 \mathrm{~N}$ acts on a mass of $5 \mathrm{~kg}$ for $10 \mathrm{~s}$. If the mass starts from rest, its velocity at the end of $10 \mathrm{~s}$ is (a) $2 \mathrm{~m} \mathrm{~s}^{-1}$ (b) $20 \mathrm{~m} \mathrm{~s}^{-1}$ (c) $200 \mathrm{~m} \mathrm{~s}^{-1}$ (d) $50 \mathrm{~m} \mathrm{~s}^{-1}$

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Key Concepts

Newton's Second Law

This law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). It is fundamental in understanding how forces affect the motion of objects, allowing us to calculate acceleration when the force and mass are known.

Impulse-Momentum Theorem

This theorem explains that the impulse applied to an object (the product of force and the time interval over which it acts) is equal to the change in momentum of the object. It links force, time, and the resulting change in velocity, and is especially useful in problems involving forces acting over a finite time period.

Constant Acceleration Kinematics

Under constant acceleration, the equations of motion, such as v = u + at, can be used to relate velocity, acceleration, and time. This concept is crucial when analyzing the motion of objects experiencing a constant net force, allowing for the prediction of future motion from initial conditions.

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