Question
A force of $P=300 \mathrm{N}$ is applied to the 60 -kg cart. Determine the reactions at both the wheels at $A$ and both the wheels at $B$. Also, what is the acceleration of the cart? The mass center of the cart is at $G$.
Step 1
The sum of forces in the x-direction equals the mass times acceleration in the x-direction. This gives us the equation: \[300 \cos 30 = 60a\] Solving this equation gives us the acceleration \(a = 4.33 \, \text{m/s}^2\). Show more…
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