00:01
Okay, so for this problem, we are asked, we're given that a connected graph with no simple circuits is called a tree, which is its definition.
00:08
We claim that a simple graph is a tree if and only if it is connected, and the deletion of any of its edges produces a disconnection.
00:16
So this is going to be a standard if and only if proof, which means that we are going to have two directions.
00:21
We're going to have one proving beat going from left to right, and then we're going to have one going from right to left.
00:30
So for the left, going from left to right direction, one of the things that we need to know is that if, is that before, actually, before we get started, we're going to let t be a tree that is a simple graph.
00:52
And then for, so we can identify any variable or any letters that we're going to be using.
00:56
So if t is a graph that is a tree, then it is connected with no simple circuit.
01:04
So we want to make sure that we identify how we're defining.
01:10
So we know it's a graph.
01:12
We know it's a tree because it is connected and no simple circuits.
01:18
Now what i want to do is i want to throw in an end of it.
01:23
So we're going to say suppose an edge e exists connecting to t.
01:34
What i want to do is i want to put in what happens if it gets, yeah.
01:40
So if e is deleted, what i want to do is i want to kind of put an n negation here.
01:48
So if e is deleted and t is still connected, then t is part of a circuit...