00:01
So here for part a, we can find the total mass of the system m.
00:04
This would be equaling 45 times the mass of a single car plus two times the mass of a single engine.
00:13
And so, or a freight train engine.
00:18
And so the mass would be equaling 45 times 5 .50 times 10 to the 5 kilograms, plus 2 times 8 .00 times 10 to the 5th kilograms.
00:36
And we have the total mass capillum being 2 .635 times 10 to the 7 kilograms.
00:45
And then we can say that the force equation for the train, if the engine pulls with a force f would be 2 times f minus the frictional force.
00:55
This should be equal to the total mass times a, the acceleration.
00:59
And so the force f would be equal to the total mass times the acceleration plus the frictional force divided by two.
01:07
This would be equaling 2 .635 times 10 to the 7th kilograms times the acceleration of we can say 0 .05 meters per second squared.
01:24
This would be plus the frictional force of 7 .5 times 10 to the 5th newtons all divided by 2 and we find that the force is equaling 1 .03 times 10 to the 6th neutens.
01:44
This would be the force of a single engine...