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A frictionless inclined plane of length 20 m has a maximum vertical height of 5 m. If an object of mass 2 kg is placed on the plane, which of the following best approximates the net force it feels?(A) 5 N(B) 10 N(C) 15 N(D) 20 N

Physics 101 Mechanics

Chapter 4

Newton’s Laws

Newton's Laws of Motion

Applying Newton's Laws

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Hey, guys, s o the problem. Ask Thio solve for the net. Force off a mass on an incline play. Let's draw the ground first. Okay, this is the inclined plane. This is the mass. So the first thing I would suggest to solve the problem is to draw the free body diagram. We know the gravity acts on the center of the mass, pointing downward with a magnitude off mg. And also there will be a normal force pointing perpendicular to the contacting surface, acting on the center off the body. And let's call it half a. Since the problem tells us that the plane is frictionless, there will not be friction on the mess. And other things we know is that the incline has a vertical height off five meters and the length of 20 meters. I'll just write it here. We know that the only way the block can move on the inclined plane is allowing the plane, so there's no way that the block have moved perpendicular to the play. So if we break down the force off gravity to the perpendicular component and the parallel components, let's break it out. That's called this angle feta let's call it theater. So we know that Ah, this is the parallel component. And this is the perpendicular component that say, Ah, the perpendicular component. The vertical one is MG science theater and the parallel component let's call it P is mg call sign feta. We know that the perpendicular component of the gravity will cancel salt with the normal force. So that night force we are looking for is the parallel component off the gravity which just m Geico Cynthia. So the only thing now we are looking for is the magnitude off CO Cynthia. We can find this. Ah, from the the block, we can see that this angle is just the same ass. This angle off the block from this we know co sign theater equals two five over 20 which is one or four. And from this we can solve that. Net force after that equals two mg Co Cynthia, which is two kilograms times. Let's say G equals to 10 for approximation and times one over four. The unit is Newton. So the answer is five new TIMS. Thank you for watching

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