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A fully charged 6.0$\mu$ F capacitor is connected in series with a $1.5 \times 10^{5} \Omega$ resistor. What percentage of the original charge is left on the capacitor after 1.8 s of discharging?

$=13.5 \%$

Physics 102 Electricity and Magnetism

Chapter 19

Current, Resistance, and Direct-Current Circuit

Electric Charge and Electric Field

Gauss's Law

Electric Potential

Capacitance and Dielectrics

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Electromagnetic Induction

Cornell University

University of Washington

University of Winnipeg

Lectures

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In this case, we have a pastor off Six Micro Farid Fast in six Microphone and their sister offer assistance. 1.5 time stamp are five home. So this is simply a capacitor connected in parallel with our sister by the tapestries Charged already. Now we know that in such a guess, Hugh the charge the capacitor is already charged, so it produces current through the circuit at the expense off its own charge on and hence the charge decreases exponentially. Andi, the charge at any time t can be found us the initial charge. Cura multiplied the keeper minus t bite out right now is the time constant, which is, in this case, our sea. The part ofthe resistance Times capacitance, which is 1.5 times 10 par five. The resistance multiplied by the capacitance, which is six times Inbar minus six. Because it's in my It's Michael. 1.5 times six is nine. So this case is 0.9 second. Now that we have this way. No charges kun on Yvonne Dynasty by 0.9. So a sequel to 1.8 seconds, we have Q Off T is equal to, you know keep our minus 1.8 by zero point time. She's too. So that's you know, Eve R minus two. How deep are minus two, which is one by e squared is equal to zero upon 14 Which means this is there a bond? One for you, Not which means the charge left after 1.8 seconds on the cab. Aster is 14% off the initial charge.

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