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A function $f$ has a slant asymptote $y=m x+b(m \neq 0)$ if $\lim _{x \rightarrow \infty}[f(x)-(m x+b)]=0$ and/or $\lim _{x \rightarrow-\infty}[f(x)-(m x+b)]=0$In exercises $43-48,$ find the slant asymptote. (Use long division to rewrite the function.) Then, graph the function and its asymptote on the same axes.$$f(x)=\frac{x^{4}-1}{x^{3}+x}$$
$y=x$
Calculus 1 / AB
Chapter 3
Applications of Differentiation
Section 6
Overview of Curve Sketching
Derivatives
Differentiation
Applications of the Derivative
Campbell University
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Hello. The functions we have in this problem is Russian inflection. Uh, why equal, uh, called every week equals the polynomial X to the fourth month Swerve on extra third class. Mhm. Ah, they want us to find the slam, I think if one exists, So what's the deal with Slams s center? It is a line mx plus B that has defined slope. And that's what this zero and this line is such that the limit will extends to grow to plus infinity. The difference between the function and the point on the line is becomes very, very small, and the limit to that difference is zero. In other words, if we had a coordinates system and let's a slant line and some function and some function whose graph is such that when X becomes greater and greater than the graph off ffx nears, this y equals MX possibility but never crosses it never touches it. Then this is the sliced s entered that off the ground. So if that happens when it tends towards plus affinity or on the other side with extends to minus infinity. So the limit here could have been written and or both sides could be true. Or if either side is true, then the line, um explicitly is smooth Him, given in the problem, is to divide using long division off for a nominal. So with X to the power of three plus six, we're going to divide the polynomial X to the fourth minus one. Why have I written it with such forget? Because then we developed polynomial. We want to stress that we have no X to the third no extra second and no term between the ones that we do who have division. We ask ourselves with what do we multiply the leading coefficient off the divisor to obtain the leading coefficient off the dividend? We multiply it x x times X to the power of three 64th six times six is X through the second subtract subtracting means change the ah change the science in ad These to annihilate each other become zero and this becomes one x squared on minus one. So this remainder is now off degree that it's more than the degree off the divisor. So we right therefore week as being the Kocian which okay, and then we have this minus X squared plus from This is in fact minus X squared plus one minus X squared plus swim over what we were dividing with X to the power of three. Well, now the trick is thing if we subtract this from a phobic So if we minus sticks is going to be, he's going to be mine. This lot here, X great Pass well over it. 36 right? If we take this to be our special with slant line than this limit would be equal to the limits off. Therefore, it minus is when extends to infinity is the same as the limit minus limit when extends the infinite or X squared plus one x to the third plus six. Now, rational functions in limits to infinity are not a huge problem because what we do here is we divide both the numerator on the denominator with the highest with the highest with the highest power of X, which is all right and we obtain limit extends to plus infinity big where divided by external plus well developed externally, its third divided by a third plus X divided by external, which is equal to the limit to infinity. Oh, this can with three of these. So we have one over plus one over the third. These to cancel and leave 1/1. This one on this eggs canceled with these three who will live. So we have one over to wear, right when it He's a huge number, then this is yeah, for almost zero from X is huge. Then this is also close to zero, and this is close to zero. So the limit we make approaches plus affinity is zero plus 0/1 0, which is zero, which is zero. And we have. But the limits off f of X 16 is equal to zero. Therefore, this here, this here is the equation off when a simple okay. Now all we need to do is check whether this is true with our graphing device. We use the Christmas here. So it to the fourth month swarm X to the fourth minus world on here We have X to the third person. That right? Excellent. Excellent. Okay, on what we see is as it becomes greater and greater the great the red A grant is the graph of the function black graph is the graph off the line the graph off the function in the line, they become closer and closer. They practically they practically overlap. So from this crap, we see that the line y equals is really this slide. I think that we were off all this time. Okay, Um but here. Right. So as ex moves towards the right far right side that if we becomes closer and closer to why it was a which means that Why? Because X is the ass enter off for weeks. The slip this went on. It's the essence of it. But it's slight because it has a slope which is not zeros. It's not a horizontal essen toe on. It's not a vertical, because the vertical has undefined slow. So this is a line with slope different zero such that the function values approach the values off the why coordinates on the line as X moves to the far right or the far left off. Yeah. Breath. So many words. There we have it, folks. Health. Bye.
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