00:01
Okay, so question was asking us the time interval that was measured by the passenger in the train, okay? which is delta t0, and delta t0 is equal to the rest length, which is a rest distance between two towers, divided by the speed, okay, the speed of train.
00:19
And we know we can come out with such equation, which is l equal to l0 over gamma.
00:23
L is the lens that was observed by the observer from the ground, and l0 is the rest length between the towers, okay? and gamma is the lowerin factor, which is equal to 1 over square root, 1 minus v square over c squared.
00:46
And l0 can be equal to gamma times l, which is equal to l over square root, 1 minus v square, over c squared.
00:53
So we know that l is given as 3 .0 kilometers.
01:01
V is given as 0 .80 c.
01:05
And c is the speed of light.
01:07
Okay? if we plug in the number, we'll have l0 is equal to square root, 1 minus 0 .80, c, and then holding square, over c square, times l, which is 3 .0 kilometer.
01:25
And this will give us l0 is equal to 1 .8 kilometers...