Question
A galvanomenter with resistance $5 \Omega$ can read upto 5 $\mathrm{m} A$. If this instrument is to be used to read upto 100 volt, then the value of resistance to be used in its series will be(a) $19.9995 \Omega$(b) $199.995 \Omega$(c) $1999.95 \Omega$(d) $19995 \Omega$
Step 1
We have a galvanometer with a resistance of \(5 \, \Omega\) that can measure up to \(5 \, \text{mA}\). We want to convert this galvanometer into a voltmeter that can measure up to \(100 \, \text{V}\). Show more…
Show all steps
Your feedback will help us improve your experience
Narayan Hari and 72 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A galvanometer of resistance 25 ohm gives full scale deflection for a current of 10 milliampere, is to be changed into a voltmeter of range 100 V by connecting a resistance of ‘R’ in series with galvanometer. The value of resistance R in ohm is (a) 10000 (b) 10025 (c) 975 (d) 9975
A galvanometer of resistance $200 \Omega$ gives full scale deflection with 15 milli-ampere current. In order to convert it into a $15 \mathrm{~V}$ range voltmeter. What is the value of resistance connected in series ? (A) $1000 \Omega$ (B) $800 \Omega$ (C) $2500 \Omega$ (D) $1500 \Omega$
To use the milliammeter of the previous question as a voltmeter of range $10 \mathrm{~V}$, a resistance $R$ is placed in series with it. The value of $R$ is a. $9 \Omega$ b. $99 \Omega$ c. $999 \Omega$ d. $1000 \Omega$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD