a-gas-collected-in-a-flexible-container-at-a-pressure-of-097-atm-has-a-volume-of-0500-l-the-pressu-2

Question

A gas collected in a flexible container at a pressure of 0.97 atm has a volume of 0.500 L. The pressure is changed to 1.0 atm. The amount of gas and the temperature of the gas do not change.
a. Will the volume of the gas increase or decrease? Explain.
b. Which equation should you use to calculate the new volume of the gas?
c. Calculate the volume of the gas at a pressure of 1.0 atm.

David Collins · Accepted Answer

question. Number three is a Boyle&#x27;s law calculation. We have a gas that is at a pressure of 0.97 atmospheres and a volume of 0.5 leaders. The pressures then change to one atmosphere. So according to Boyle&#x27;s law, P one V one equals P two V two. So if we have an initial pressure of 0.97 atmospheres and an initial volume of 05 leaders, then if the pressure increases toe 1.0 atmospheres, what must happen to the new volume? We see that if the pressure has increased, which it has, the volume is going to have to decrease. So if this pressure has now increased to something above 0.97 this volume needs to decrease to something below 0.50 And when we carry out the calculation for the new volume, that&#x27;s exactly what we get. A smaller volume, zero point 485 leaders, or to just two significant figures, 0.49 leaders

Salamat Ali · Answer

for a constant temperature. Constant breacher. Um, initial pressure times initial William is equal to the file. Will you times the final pressure. He&#x27;ll find the pressure saurian times final. William, Our initial pressure we have is there a point? So the initial William we have got rather 0.5 and 0.5 a meter cube times the pressure you in four. Hmm. And then finally, pressure. We have also won and we were asked to find the William we f So we&#x27;ll straighten our soul for the f ree Jesu to meet your cube here.

Katherine Mccandless · Answer

According to Boyle&#x27;s law. Pressure and volume of a gas are inversely related, and so what that means is that if the pressure is increased, the volume should decrease or if the pressure decreases, the volume would increase. So if we have a gas that initially at a pressure of two atmospheres and we changed the pressure just six atmospheres, this is an increase in pressure. So I would expect the volume to decrease. If in our next example we start off with the initial pressure at two and we keep it, it too atmospheres. There&#x27;s no change in the pressure, so I would expect the volume to stay the same. And finally, in our last example, the pressure goes from two atmospheres to 0.4 atmospheres, which is decreasing the pressure so the volume should increase.

Katherine Mccandless · Answer

According to Boyle&#x27;s law, the relationship between pressure and volume can be described. Yeah, the pressure increases. The volume of a gas will decrease score. If the pressure decreases, the volume will increase. This is called Boyle&#x27;s Law. It is an example of an inverse relationship. So if we start off with a gas that has an initial volume of four leaders, if we change that Volume 22 leaders, the volume decreases. So that would indicate that the pressure should increase. If instead, we change the volume 2 12 leaders or increase the volume. The pressure should decrease our last example in which we changed the volume 2.4 leaders. This is a decrease in volume, so it&#x27;s just like our first example. We would expect the pressure to increase.

Matthew Potter · Answer

this problem were asked what happens to the volume in four different cases? A. The CMP clams to the volume on the pressure and temperature change. And since a problem didn&#x27;t see anything about gas escaping or being added, we&#x27;re going to assume that an number of moles always stays safe. So looking at our ideal gas law, we just need to make up share. It always balances. Now this problem seems pretty straightforward because generally pressure is either going up, were down by to, so it&#x27;s either doubling our having, and the temperature seems to do the same. But here&#x27;s the thing in the problem. It gives all of the units for Temperature s Celsius, and we don&#x27;t want to use Celsius because that&#x27;s not what the universal gas constant is in. And because it&#x27;s relative for pretty much anything exciting, we need it to be in Calvin. If we do that, you&#x27;ll find that rather than the temperature doubling or having, in most cases, it&#x27;s going down by a smaller amount. What do I mean by this? Well, to comfort, the conversion between these is one of the easiest. You just need to add 273 to the degree Celsius Central have it and Kelvin. So how does that change? Let&#x27;s look at the first problem where the pressure is going from two atmospheres to one atmosphere. Now, if we convert the temperature, we find that instead of it is actually going from for 73 Copa and 23 70. Excuse me that she wrote it wrong. 2 373 Calvin. So first, let&#x27;s just consider pressure. So it&#x27;s going down, which normally would cause the volume to go up. But we also have temperature going down, but it&#x27;s not going down by as much. So maybe we&#x27;ll just say that well, the volumes increasing. It&#x27;s not as much as if the temperature was constant. So this case don&#x27;t put a bombs in here. Claims increasing because while the temperature is decreasing, which would balance out, the question is not disgracing nearly as much as the pressure is decreasing For this next one, the pressure is going from one atmosphere to three atmospheres, so it&#x27;s tripling and it looks like the temperatures in tripling to. But really it&#x27;s going from 3 73 k toe 5 73 k. So we have pressure tripling, which normally cause the Volume two. Deke Respectable. Now let&#x27;s consider temperature. The temperature is increasing, but not quite as much as the pressure. So in this case, volume is still going to decrease, cause that&#x27;s what is needed to balance out the equation. Now let&#x27;s look at this next heart. This is one where the temperature might look a little strange and Celsius have three atmospheres going to six atmospheres for the pressure, once again doubling. And if you do the conversion, you find that you have 200 Kelvin going to 400 Calvin. So this is doubling. Let&#x27;s get some color in there. So the pressure is doubling and the tempers shares actually doubling, which means volume. I was actually staying the same in this case. Look at the last case were asked about. We have 0.2 atmospheres going to point for atmospheres, and we have. And while this is increase in the pressure, I mean the temperature is actually decreasing. If we do the math, this is where I&#x27;m from 5 73 to 4 73 Calvin. So let&#x27;s look at the English. We have this increasing. That&#x27;s because volume to decrease. But in this case, temperatures also decreasing. Which forces the volume toe actually decrease more Now we&#x27;re not asked necessarily about the how much they&#x27;re decreasing. Were not asked to self these. So you don&#x27;t need to plug anything in. But what we need to know is that volume is decreasing in this problem. Hope this helps, does you?

David Collins · Answer

to calculate the new volumes. We simply need to know what is changing in which gas law to use for part a. What is changing is the pressure. If the pressure is changing then the pressure and the volume are related to each other through Boyle&#x27;s law. P. One V. One equals P. T. V two. Rearranging this equation. We can solve for the new volume by taking the first pressure 752 Tour, multiplied by the first volume, 5.12 leaders And divide that by the second pressure. But the pressure units need to be the same. So let&#x27;s convert the 1.88 atmospheres into tour by multiplying by 760 And we get 2.69 L. Next we have a change in temperature. So we&#x27;re going to use Charles Law. Be one over T one equals V two over T two. So V two Is going to be equal to V one 5.12 multiplied by T two. But in Kelvin, so we need to add to 73 to our C temperature And then divide by T one, Which was 21°C,, which will also add to 73 to to get it into Kelvin, And we get 7.80 leaders.

Problem

The gas pressure in an automobile tire was 1.0 at…

Problem 3 Easy Difficulty

Answer

(a) The volume will decrease. See explanation.
(b) The equation p1V1 = p2V2 would be used since temperature and amount of gas are constant.
(c) 0.49 L

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(a) The volume will decrease. See explanation.(b) The equation p1V1 = p2V2 would be used since temperature and amount of gas are constant.(c) 0.49 L

Living by Chemistry

Theodore D.

Lizabeth T.

Nadia L.

Jake R.

Intro To Chem - Introduction

Classification and Properties of Matter

Angelica M. StacyLiving by Chemistry

Theodore D.

Lizabeth T.

Nadia L.

Jake R.

(a) The volume will decrease. See explanation.
(b) The equation p1V1 = p2V2 would be used since temperature and amount of gas are constant.
(c) 0.49 L

Angelica M. Stacy

Living by Chemistry