Question
A gas expands $0.25 \mathrm{~m}^{3}$ at Constant Pressure $10^{3}\left(\mathrm{~N} / \mathrm{m}^{2}\right)$ the work done is(A) $250 \mathrm{~J}$(B) $2.5$ erg(C) $250 \mathrm{~W}$(D) $250 \mathrm{~N}$
Step 1
Step 1: The work done by a gas at constant pressure is given by the formula: \[ W = P \Delta V \] where \( P \) is the pressure and \( \Delta V \) is the change in volume. Show more…
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