Question
A gas mixture contains $1.25 \mathrm{~g} \mathrm{~N}_{2}$ and $0.85 \mathrm{~g} \mathrm{O}_{2}$ in a $1.55-\mathrm{L}$ container at $18^{\circ} \mathrm{C}$. Calculate the mole fraction and partial pressure of each component in the gas mixture.
Step 1
The molar mass of N2 is approximately 28 g/mol and the molar mass of O2 is approximately 32 g/mol. Number of moles of N2 = mass/molar mass = 1.25 g / 28 g/mol = 0.0446 mol Number of moles of O2 = mass/molar mass = 0.85 g / 32 g/mol = 0.0266 mol Show more…
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A gas mixture contains 1.25 $\mathrm{g} \mathrm{N}_{2}$ and 0.85 $\mathrm{gO}_{2}$ in a 1.55 $\mathrm{L}$ container at $18^{\circ} \mathrm{C}$ . Calculate the mole fraction and partial pressure of each component in the gas mixture.
A gas mixture contains 1.25 g N2 and 0.85 g O2 in a 1.55-L container at 18 C. Calculate the mole fraction and partial pressure of each component in the gas mixture.
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