00:01
So this question belongs to the laws of thermodynamics in which we have a gas with adiabetic constant gamma equals to 1 .4 occupies volume v1, it is equals to 5 .0 liter at pressure p1 equals to 100 k pascal.
00:15
Now for the part a, we have to determine the final pressure p final or we can say that p2, when the gas is compressed adiabatically to volume v2 equals to 2 .5 liter.
00:29
So from the adiabetic equation, we can write that p1 v1 to the power gamma, this is equals to p2 v2 the power gamma.
00:36
So from here after rearranging we get p2, it is equal to v1 by v2 to the power gamma, multiplied by pressure p1.
00:44
So v1 is 5 .0 liter divided by v2 is 2 .5 liter to the power 1 .4, mudplated by p .1, which is 100 kilo pascal.
00:53
So from here after solving, we get pressure p2, it is equals to 2 .6 .5.
00:59
Multiplied by 10 to the power 5 pascal...