00:01
Okay, so for this problem, we're given that we have this kind of hemisphere shape, and we're told that there's an electric field going like this, and we're asked to find the flux through the flat surface and through the curved surface.
00:14
And so let's start with the flat surface.
00:17
Oh, and actually let me write down my givens before i get any further.
00:21
So this electric field is 2 .5 newtons per coulum.
00:27
That's a beautiful five.
00:31
That's okay.
00:32
It's not a critical part of the problem.
00:34
And the radius is 0 .0568 meters, 3 sig figs.
00:43
Okay.
00:44
And we're asked to find the flux, the flat surface.
00:47
And so the electric fields uniform, so the integral of e .da is just going to be the electric field times the area and the cross -sectional areas, pi r squared.
00:59
So when i plug that into a calculator, i got 0 .0 .0 .1 .2.
01:03
And then notice that it's negative because we generally define the area of vectors is going out...