Question
(a) Give an example of an interpolating polynomial through $n+1$ points that has degree $<n$. (b) Can you explain, without referring to the explicit formulas, why all the Lagrange interpolating polynomials based on $n+1$ points must have degree equal to $n$ ?
Step 1
An interpolating polynomial for a given set of points \((x_0, y_0), (x_1, y_1), \ldots, (x_n, y_n)\) is a polynomial \(p(x)\) such that \(p(x_i) = y_i\) for all \(i = 0, 1, \ldots, n\). Show more…
Show all steps
Your feedback will help us improve your experience
Sara Sasani and 51 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Either give an example of a polynomial with real coefficients that satisfies the given conditions or explain why such a polynomial cannot exist. $P(x)$ is a fourth-degree polynomial with no turning points.
Polynomial and Rational Functions
Polynomial Functions and Models
Either give an example of a polynomial with real coefficients that satisfies the given conditions or explain why such a polynomial cannot exist. $P(x)$ is a third-degree polynomial with one $x$ intercept.
Either give an example of a polynomial with real coefficients that satisfies the given conditions or explain why such a polynomial cannot exist. $P(x)$ is a third-degree polynomial with no $x$ intercepts.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD