(i) For $\mathrm{H}_{2} \mathrm{SO}_{3}$, after donating a proton, it becomes $\mathrm{HSO}_{3}^{-}$. So, the conjugate base of $\mathrm{H}_{2} \mathrm{SO}_{3}$ is $\mathrm{HSO}_{3}^{-}$.
(ii) For $\mathrm{HSO}_{3}^{-}$, after donating a proton, it becomes
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