00:01
In this question we are given a 48 volts battery and we are given two resistors.
00:10
So one is a 4 -oom resistor and the other is a 96 -oom resistor.
00:19
We want to find one is the current as well as the power for each one of the resistor in two different scenarios.
00:28
So first one will be in series.
00:31
So when they are in series, the current passing through them is the same.
00:38
They have a common current.
00:41
The current is based on the total resistance of the circuit and the total potential difference, or potential drop.
00:49
So i goes to v over r, that is 48 folds.
00:55
And the total resistance is 96 plus 4, which is 100 oms.
00:59
This will give us your 0 .48 ampute.
01:10
Next to find the power for each one of them, we just take power equals to i square r, where i is already found.
01:20
So there's 0 .48, so we just take that square, multiplied by 4, for the 4 om.
01:28
So power for the 4 o resistor will be just i square times 4, which is 92, sorry 0 .922 watts whereas power for the 96 oms would be 22 .1 watts.
01:58
Alright and now moving on to the parallel case...