00:01
Okay, so we're given this angle between the ray from the diver and the normal line, and we are going to use it to find this angle, which i called theta f, between the ray from the instructor in the normal line, which we'll then use to find h, and that's part a.
00:19
So we'll start with snell's law, which tells us that nf sine of theta f equals n i, sine theta i.
00:35
We can solve for theta f, and plug in all those values, and we'll find that it is inverse sign of 1 .33 times a sign of 25 over 1 .0, which tells us that theta f is 34 .3.
01:07
Degrees.
01:09
And then we can use this triangle here, since we know this horizontal length, and now we know theta f to find h.
01:17
So using that triangle, tan theta f is opposite over adjacent, which is 2 .0 meters over h.
01:26
Solving for h, we find that h is 2 .0 meters over a tangent of 34 .3 degrees.
01:40
And that tells us the height of the diver, which is 2 .93 meters...