A golf ball travels with a speed of 90.0 m / s. By what fraction does its relativistic momentum

step 1 Here in this question, p minus m u divided by m u is equal to gamma m u minus m u divided by m u

A golf ball travels with a speed of 90.0 m / s. By what...

A golf ball travels with a speed of $90.0 \mathrm{m} / \mathrm{s}$. By what fraction does its relativistic momentum magnitude $p$ differ from its classical value $m u$ ? That is, find the ratio $(p-m u) / m u$.

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Key Concepts

Relativistic Momentum

Relativistic momentum is a modification of the classical momentum formula to account for the effects of special relativity. It is given by p = ?m u, where ? is the Lorentz factor, m is the rest mass, and u is the velocity. This concept illustrates how momentum increases more dramatically at speeds approaching the speed of light compared to the classical expectation of m u.

Lorentz Factor

The Lorentz factor, defined as ? = 1/?(1 - u²/c²), quantifies the time dilation, length contraction, and mass variation effects as predicted by special relativity. It becomes significant when the speed u is a non-negligible fraction of the speed of light (c), effectively modifying classical physical quantities like momentum and energy.

Low-Velocity Approximation (Taylor Expansion)

When dealing with speeds that are very low compared to the speed of light, the Lorentz factor can be approximated via a Taylor series expansion, yielding ? ? 1 + (1/2)(u²/c²). This approximation allows us to estimate the small differences between relativistic and classical descriptions of momentum by revealing that the correction term (p - m u)/m u is approximately (1/2)(u²/c²) for low velocities.

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