00:01
So here the moment of inertia, we have a quick diagram of the system here.
00:04
The moment of inertia of a rod is going to be equal to one -third ml squared, the length of the rod.
00:12
And the moment of inertia of a sphere would be equaling then two -fifths times the mass times the radius of the sphere squared.
00:24
And so given this, we can use the parallel axis theorem where the moment of inertia equals the moment of inertia at the center, plus m x squared, where x in this case would be the distance of the pivot point to the center of the mass.
00:43
And so the period t would be equalling to 2 pi multiplied by the square root of the moment of inertia i from the parallel axis theorem, mass sub t, which is a mass total, g.
01:03
And so the moment of inertia of the system i would be equaling, moment of inertia of the rod plus the moment of inertia of a sphere plus m l squared.
01:19
So in this case this would equal then one third m l squared plus two fifths m and then for r we can say that this would be l squared over four plus m l squared.
01:41
And so we can say that then i, after simplifying, i is going to be equal to 43 ml squared over 50, over 30, my apologies.
01:58
So given this, this would be our answer for a...