Question
A grating has exactly 8000 slits uniformly spaced over $2.54 \mathrm{~cm}$ and is illuminated by light from a mercury vapor discharge lamp. What is the expected angle for the third-order maximum of the green line $(\lambda=546 \mathrm{~nm}) ?$
Step 1
First, we need to find the distance between each slit, which we can call "d". To do this, we can divide the total length of the grating (2.54 cm) by the number of slits (8000). d = (2.54 cm) / (8000) = 3.175 x 10^-4 cm = 3.175 x 10^-6 m Show more…
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Gratings A grating has exactly 8000 slits uniformly spaced over $2.54 \mathrm{cm}$ and is illuminated by light from a mercury vapor discharge lamp. What is the expected angle for the third-order maximum of the green line $(\lambda=546 \mathrm{nm}) ?$
Light of wavelength 546 $\mathrm{nm}$ (the intense green line from a mercury source) produces a Young's interference pattern in which the second minimum from the central maximum is along a direction that makes an angle of 18.0 $\mathrm{min}$ of arc with the axis through the central maximum. What is the distance between the parallel slits?
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