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Carnegie Mellon University

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Problem 45 Easy Difficulty

A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 40.0 vibrations in 30.0 s. Also, a given maximum travels 425 $\mathrm{cm}$ along the rope in 10.0 s. What is the wavelength?

Answer

0.319$m$

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Video Transcript

beat of the waves. V would be equaling the displacement with respect to time, the change in displacement with instructor time. So this would be 425 centimeters divided by 10 seconds, and this is giving us 42.5 centimeters per second and the frequency would be the number of vibrations per second. And so the frequency would simply be equaling 40 0.0 vibrations in 30 0.0 seconds. And so finding the wavelength would simply be equaling the velocity divided by the frequency. And so this would be equaling. We could say 40 2.5 centimeters per second, divided by 40.0 vibrations for every 30.0 seconds. And we find that then the wavelength is equaling 31 0.9 centimeters. This would be our final answer. That is the end of the solution. Thank you for watching

Carnegie Mellon University
Top Physics 102 Electricity and Magnetism Educators
Elyse G.

Cornell University

Zachary M.

Hope College

Aspen F.

University of Sheffield

Meghan M.

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Physics 102 Electricity and Magnetism Bootcamp

Lectures

Join Bootcamp