First, we need to convert the given temperatures from Celsius to Kelvin. To do this, we add 273.15 to each temperature:
$T_H = 1200^{\circ} \mathrm{C} + 273.15 = 1473.15 \mathrm{K}$ (high temperature)
$T_L = 20^{\circ} \mathrm{C} + 273.15 = 293.15 \mathrm{K}$
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