Given that the thermal efficiency is $25\%$ or $0.25$, and the heat expelled to the cold reservoir is $1.2 \times 10^{6} \mathrm{~J/h}$, we can rearrange the formula to solve for $W$:
\[0.25 = \frac{W}{Q_C + W}\]
\[0.25Q_C + 0.25W = W\]
\[0.75W = 0.25 \times 1.2
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